Question

Two condensers of 20μF and 5μF are connected in series and a third condenser of 6μF is connected in parallel with this combination. Find the equivalence capacitance.

Need solution step-by-step!!​

Answer 1

In series

1/Cs = 1/20 + 1/5

= 20 ×5 /25

Cs = 4uf

In parallel,

Cp = 4 + 6

Cp = 10 uf

Mark Brainliest

Answer 2

Given,

The capacitance of the first condenser = 20μF

The capacitance of the second condenser = 5μF

The capacitance of the third condenser = 6μF

To Find,

The equivalence capacitance =?

Solution,

The first and the second condensers are connected in series.

$\frac{1}{C_{S} } = \frac{1}{C_{1} } + \frac{1}{C_{2} } \\\frac{1}{C_{S} } = \frac{1}{20} } + \frac{1}{5} } \\\frac{1}{C_{S} } = \frac{5}{20 } \\ {C_{S} = 4$

Hence, $C_{S} = 4$μ$F$

Now, $C_{S}$ is connected in parallel with 6μ$F$.

The equivalent capacitance will be:

$C = 5$μ$F$ + 6μ$F$   (Since it is connected in parallel)

$C = 11$μ$F$

Hence, the equivalence capacitance will be $11$μ$F$.