Question

Two condensers of unequal capacities are connected in series across a constant voltage d.c.

source. The ratio of the potential differences across the condensers will be​

Answer 1

Answer:

b

Explanation:

direct proportion to their capacities

inverse proportion to their capacities

direct proportion to the square of their capacities

inverse proportion to the square root of their capacities

Answer 2

Answer:

$\frac{V_1}{V_2} = \frac{C_2}{C_1}$

Explanation:

• When a voltage is delivered from one plate to the other, the parallel plates of this capacitor accumulate opposing charges.
• According to the equation Q = C V, where Q is the charge in Coulombs, C is the capacitance in Farads, and V is the potential difference between the plates in volts, the amount of charge that transfers into the plates relies on both the capacitance and the applied voltage.

Let the two capacitors be C1 and C2, and the Voltage through each of them is V1 and V2 respectively. The amount of charge flowing through each capacitor will be equal i.e. Q.

For the first capacitor, $Q$ = $C_1V_1$               ......   (i)

For the second capacitor, $Q=C_2V_2$        ......   (ii)

Comparing (i) and (ii),

$C_1V_1=C_2V_2$

$\implies \frac{V_1}{V_2} = \frac{C_2}{C_1}$

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