Question

two conducting spheres A and B of the same size are situated at some distance apart each has a charge of + q coulomb and they repel each other with a force of 10 to the power minus 5 Newton third conducting uncharged spare C of same size is first touched with a and then with b and then placed exactly between A and B calculate the resultant force on c.​

Answer 1

charge on each sphere A n B= +q

if separation b/w A n B is r,then

F=K.q2/r2=10^-5 N

when a similar but uncharged sphere c is placed in contact wid a,each sphere shares q/2 equally.

thus,force on C due to A =K(q/2)2 / (r/2)2 = Kq2/r2,along AC

force on C due to B = Kq.q/2 /(r/2)2 = K.2q2/r2,along BC

since these forces act in opp directions,net force on C is:

F'= K.2q^2/r^2 - K.q^2/r^2

= kq2/r2=10^-5

Answer 2

Answer:

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ur ans is...

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Explanation:

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