two conducting wires of same length made of same material both are hollow one of outer diameter 3mm and inner diameter 2mm while the other with outer diameter 2mm and inner diameter 1mm. the ratio of irresistance will be???
5:3/9:4/3:1/3:5
Answers
Ratio of resistance will be 3 : 5
Explanation:
Wire A
Outer Diameter = 3 mm => Outer radius = 3/2 mm
inner Diameter = 2mm => Inner radius = 1 mm
Cross Section = π ( (3/2)² - 1²) = π (5/4) mm²
Wire B
Outer Diameter = 2 mm => Outer radius = 1 mm
inner Diameter = 1 mm => Inner radius = 1/2 mm
Cross Section = π ( 1² - (1/2)² ) = π (3/4) mm²
R = ρL/A
ρ is Same as same material
L is same as Same length
=> Ra = ρL/ π (5/4)
Rb = ρL/ π (3/4)
=> Ra/Rb = 3/5
=> 3 : 5 will be resistance
ratio of resistance will be 3 : 5
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