two conducting wires of same materialand of equal lengths, resistance, and resistivity having ratio 1:2. their diameter ratio will be------a) 1:2 b) 1:4 c) 4:1 d) 1:square root of 2
Pls give solution tooo
Answers
Answered by
4
ANSWER.....
THERE DIAMETERS RATIO WILL BE... 4:1
SOLUTION :--
R1=1/area
R2=1/area
R1/R2=πr2^2/πr1^2
R1/R2=4:1
HOPE IT HELPS
THERE DIAMETERS RATIO WILL BE... 4:1
SOLUTION :--
R1=1/area
R2=1/area
R1/R2=πr2^2/πr1^2
R1/R2=4:1
HOPE IT HELPS
ritz11177:
can u give the process tooo
Answered by
1
Answer: d) 1/√2
Explanation:
Let the resistivity of first wire is ρ₁ and of second wirte is ρ₂
Given,
ρ₁/ρ₂ = 1/2
Now,
We know that,
resistivity of a wirre is directly proportional to its cross section area.
If the cross section area of wires are A₁ and A₂ respectively,
ρ₁/ρ₂ = A₁/A₂
A₁/A₂ = 1/2
If the radius of wires are r₁ and r₂ respectively,
A₁ = πr₁²
A₂ = πr₂²
A₁/A₂ = r₁²/r₂²
1/2 = r₁²/r₂²
r₁/r₂ = 1/√2
Ratio Of diameter:-
D₁/D₂ = 2r₁/2r₂
D₁/D₂ = 1/√2
Hence, Option d) is correct.
Note:- There is a conflict in the question. It is given in the question that both wire are made of same material ; On other hand its given that ratio of their resistivity is 1:2 Which is not possible. Resistivity of same material should be same
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