Two conducting wires of the same material and equal length and equal diameters are first corrected in series and then in parallel in an electric circuit. Calculate the ratio of heat produced in series and parallel combination
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Let Resistance of the materials be R
In parallel combination
1/Req = 1/R +1/R
Therefore, Req= R/2 ohm
Hence Heat produced= I²Rt where I and t are current and time respectively
= I²R/2*t Joules
In series combination,
Req= R+R= 2R ohm
Therefore Heat produced= I²2R*t Joules
Ratio of heat produced in series to parallel = I²2R*t/ I²R/2*t
= 4:1
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