Question

Two conducting wires of the same material and equal length and equal diameters are first corrected in series and then in parallel in an electric circuit. Calculate the ratio of heat produced in series and parallel combination

Answer 1

Answer:

Let Resistance of the materials be R

In parallel combination

1/Req = 1/R +1/R

Therefore, Req= R/2 ohm

Hence Heat produced= I²Rt where I and t are current and time respectively

= I²R/2*t Joules

In series combination,

Req= R+R= 2R ohm

Therefore Heat produced= I²2R*t Joules

Ratio of heat produced in series to parallel = I²2R*t/ I²R/2*t

                                                                        = 4:1

PLS MARK ME BRAINLIEST!!!!!!!!!!!

 

Explanation: