Two conducting wires of the same material and of equal lengths and equal diameter are first connected in series and then parallel in a circuit across the same potential difference. the ratio of the heat produced in series and paralles combinations would be-
Answers
Heat produced in the circuit is inversely proportional to the resistance R.
Let RS be the equivalent resistances of the wires if connected in series and RP be the equivalent resistances of the wires if connected in parallel
Then RS =R+R=2R ---->(1)
And 1/ RP = 1/R +1/R
1/ RP = 2/R
Or RP =R/2 ----->(2)
Now the ratio of heat produced is given by:
\huge\frac{H_S}{H_P}
H
P
H
S
= \huge\frac{V^2t}{R_S}÷\frac{V^2t}{R_P}
R
S
V
2
t
÷
R
P
V
2
t
\huge\frac{V^2t}{R_S}× \frac{R_P}{V^2t}
R
S
V
2
t
×
V
2
t
R
P
\huge\frac{R_P}{R_S}
R
S
R
P
\huge\frac{R/2}{2R}
2R
R/2
\huge\frac{R}{4R}
4R
R
\huge\frac{1}{4}
4
1
\huge\fbox{ 1 : 4 }
1 : 4
Sanjay Sen first off we saw that all the lengths radius and resistance was equal so then first we calculated the resistance by a formula RO I'll be ok and then after that we calculated the in series and parallel properly then after that we then after that we calculated our current by equals to be upon the after that we got our current and after that we saw that I will be called because our VL amines radius volume length area everything is equal potential difference also provide time is it is equal then after that we compared sheet by series it but I square to m square Aarti then after that we saw week calculator them then we did Heath of series upon heat of parallel then we calculated we got one ratio 4 is the answer hope it helps please mark it as brainliest.
