Question

two conductors A and B have their lengths in ratio 4 : 3, area of cross-section in ratio 1 : 2 and their resistivity in ratio 2 : 3. What will be the ratio of their of their resistances?




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Answer 1

Answer:

Hence the ratio of their resistances is 16 : 9.

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Answer 2

Given:

Lengths of two conductors 4:3

Cross-sectional areas of two conductors 1:2

The resistivity of two conductors 2:3

To find:

The ratio of their resistances

Solution:

1) Let the ratio of the length is 4x:3x

Let the ratio of the cross-section area of two conductors y:2y

Let the ratio of the resistivity of two conductors 2z:3z

2) Resistance = ρl/A

The Resistance of the first conductor = R = 2z.4x/y

The Resistance of the second conductor = R' = 3z.3x/2y

• R/R' = 2z.4x/y ÷ 3z.3x/2y

• R/R' = 2z.4x.2y / 3z.3x.y

• R/R' = 16/9

The ratio of their resistances 16:9