Physics, asked by Rano38, 15 days ago

Two conductors A and B of resistances 10Ω and 15Ω respectively are first joined in series and then in parallel. The potential difference applied is 20V.
(i) In which case would the equivalent resistance be less and by how much?
(ii) How much would be the power dissipated in the 10Ω resistor when they are connected in series.​

Answers

Answered by itzmecuterose
2

Answer:

Given : R

1

=10Ω R

2

=20Ω R

3

=30Ω

Equivalent resistance of parallel combination

R

eq

1

=

R

1

1

+

R

2

1

+

R

3

1

R

eq

1

=

10

1

+

20

1

+

30

1

⟹R

eq

=5.45 Ω

Explanation:

hope it helps u-hh

Answered by ayaanalisk60
0

Answer:

(a) Parallel arrangement is shown in Fig,12.57 (a) and series in combination of Fig.12.57(b)

(b) In parallel combination the voltage across conductors A and B will be same.

(c ) In series arrangement the current through conductors A and B is same.

(d) In parallel arrangement equivalent resistance Rp is given by :

1Rp=15+110=2+110=310⇒Rp=103=3.33Ω

In series arrangement equivalent resistance Rs is given by Rs=5+10=15Ω.

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