Question

two conductors A and B of resistances 5 and 10 are first connected in series and then in parallel to a voltage of 20v in each case a) draw the circuit diagram in each case b) in which combination voltage will be same c) in which combination current will be same d) calculate the equivalent resistance for each arrangement​

Answer 1

Answer:

WHENEVER RESISTANCE ARE IN PARALLEL THEIR VOLTAGES ARE SAME

AND WHEN THEY ARE IN SERIES THEIR CURRENT ARE  

SAME...

EQUIVALENT RESISTANCE WHEN IN PARALLEL IS = 1/R [equivalent] = 1/R1 + 1/R2 + 1/R3 and so on

BUT HERE WE NEED ONLY 1/R [equivalent]  = 1/R1 + 1/R2

SO NET IS 3.33333 Ω

AND IN SERIES.... ADD BOTH SIMPLY 15 Ω

Explanation:

LET ME TELL YOU A SHORT METHOD OF DOING TWO RESISTANCE PROBLEM CONNECTED IN PARALLEL IN A SHORT WAY

USE FORMULA        [R1] [R2]  /  [R1] + [R2]

USE ONLY FOR TWO RESISTANCE CONNECTED IN PARALLEL NEVER USE THIS FORMULA FOR RESISTANCE MORE THAN TWO RESISTANCES

Answer 2

Answer:

Explanation:

a). In the attachment,

b). Voltage across A and B will be same in parallel connection

c). current in A and B will be same in series connection

d). ->parallel combination ,

    R(p) = R1R2 / R1 + R2

    R(p) = 5*10 / 5 + 10

    R(p) = 50/15

    R(p) = 10/3

    R(p) = 3.33 W

    -> series connection ,

    R(s) = R1 + R2

    R(s) = 5 + 10

    R(s) = 15 W

PLEASE MARK ME AS BRAINLIEST☻