Question

Two conductors are carrying 1000A and

5000A currents respectively are 5cm apart. The

force per meter length between two conductors?


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Answer 1

Answer:

Ans :- is 5

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Answer 2

Step-by-step explanation:

Given Two conductors are carrying 1000 A and 5000 A currents respectively are 5 cm apart. The force per meter length between two conductors?

• So the current I1 = 1000 A
•            Current I2 = 5000 A
•        Distance = 5 cm = 5 x 10^-2 m
• We need to find the force per meter length between two conductors.
• Therefore Torque developed force will be
•                                        F = μo I1 I2 / 2 π d
•                                           = 4π x 10^-7 x 1000 x 5000 / 2 π x 5 x 10^-2
•                                            = 4 x 5,00,000 x 10^-7 x 10^2
•                                           = 20 N

Reference link will be

https://brainly.in/question/39263380