Two conductors have resistance r1 and r2 at 0
c. their temperature coefficients of resistances are show that temperature coefficients of their equivalent resistances when joined in parallel
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Rs=R+R=2RRs=R+R=2R
Rs(1+αsθ)=R(1+α1θ)+R(1+α2θ)Rs(1+αsθ)=R(1+α1θ)+R(1+α2θ)
⇒αs=(α1+α2)/2
Hope this helps you...:)
Rs(1+αsθ)=R(1+α1θ)+R(1+α2θ)Rs(1+αsθ)=R(1+α1θ)+R(1+α2θ)
⇒αs=(α1+α2)/2
Hope this helps you...:)
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