Question

Two cones of radius p and q units and of equal
height are melted to form a solid sphere of radius R.
Then what was the height of the cones,​

Answer 1

Answer:

Let the radius of the cone = R

and Height of a cone = r [Given]

Volume of cone =

1 \div 3\pi {}^{2} h

Now,

Volume of sphere = Volume of cone

= )\frac{4}{3} \pi ^{3} = \frac{1}{3} ^{2} h \\ = ) \: 4r^{2} = r^{2} (r) \\ = )r = 2

thus,the radius of the base of cone =2r