two congruent circles intersect each other at point A and B through point a any line segment PQ is drawn so that P and Q lie on the two circles prove that BC is equals to BQ
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Two congruent circles intersect each other at O. Through A any line segment PAQ is drawn so that P and Q lie on the circle. Prove that BP = BQ. That means they intersect only at one point O. ... The same sum is given in my textbook and it's written that circles intersect at A and B and P and Q lie on the two circles.
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