Question

two congruent circles with centres o and o' intersect at two points a and b. then prove that angle aob=angle ao'b​

Answer 1

Answer:

prove by congruency

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feel free to ask any doubts

Answer 2

Answer with Step-by-step explanation:

Let r  be the radius of circle withe center O and r' be the radius of circle with center O'

OA=OB=r

O'A=O'B=r'

When two congruent circles are congruent then their  radius are equal.

Therefore, bu using this property

r=r'

In triangle AOB and AO'B

$OA=O'A$

$OB=O'B$

Because radius of circles are equal

$AB=AB$

Reason:Reflexive property

$\triangle$AOB$\cong\triangle$ AO'B

Reason: SSS postulate

$\angle AOB=\angle AO'B$

Reason: CPCT

Hence, proved.

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