Two conically shaped pieces of metal half volumes in the ratio 64:27
Find the ratio of their height
Find the ratio of their base rader
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Let the side of 1st cube be a
& the 2nd cube be b
\frac{vol \: of \: 1st \: cube}{vol \: of \: 2nd \: cube} = \frac{27}{64}
a³/b³=27/64
\frac{a}{b } = \frac{3}{4}
T.S.A of 1st /T.S.A of 2nd=6a²/6b²
=a²/b²
=(3)²/(4)²
=9/16
T.S.A of 1st:T.S.A of 2nd=9:16
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