Two consecutive angles A and B of a parallelogram ABCD are in the ratio 3:2 , find its angles
Answers
Two consecutive angles A and B of a parallelogram ABCD are in the ratio 3:2 , Find its angles.
SOLUTION➡
Let the common ratio be x
3x , 2x
Angle A = Angel C [ opposite angels of parallelogram are equal]
Similarly,
Angle B = Angel D
_______________________________
Now ,
Angle A + Angle B + Angle C + Angle D = 360° [ Angel Sum Property of Quadrilateral]
=> 3x + 2x + 3x + 2x = 360°
=> 6x + 4x = 360°
=> 10x = 360°
=> x= 36°
______________________________
Angle A = 3x = 3× 36 = 108°
Angle B = 2x = 2× 36 = 72°
Angle C = 3x = 3× 36 = 108°
Angle D = 2x = 2× 36 = 72°
Answer:
Two consecutive angles A and B of a parallelogram ABCD are in the ratio 3:2 , Find its angles.
SOLUTION➡
Let the common ratio be x
3x , 2x
Angle A = Angel C [ opposite angels of parallelogram are equal]
Similarly,
Angle B = Angel D
_______________________________
Now ,
Angle A + Angle B + Angle C + Angle D = 360° [ Angel Sum Property of Quadrilateral]
=> 3x + 2x + 3x + 2x = 360°
=> 6x + 4x = 360°
=> 10x = 360°
=> x= 36°
______________________________
Angle A = 3x = 3× 36 = 108°
Angle B = 2x = 2× 36 = 72°
Angle C = 3x = 3× 36 = 108°
Angle D = 2x = 2× 36 = 72°
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Two consecutive angles A and B of a parallelogram ABCD are in the ratio 3:2 , Find its angles.
SOLUTION➡
Let the common ratio be x
3x , 2x
Angle A = Angel C [ opposite angels of parallelogram are equal]
Similarly,
Angle B = Angel D
_______________________________
Now ,
Angle A + Angle B + Angle C + Angle D = 360° [ Angel Sum Property of Quadrilateral]
=> 3x + 2x + 3x + 2x = 360°
=> 6x + 4x = 360°
=> 10x = 360°
=> x= 36°
______________________________
Angle A = 3x = 3× 36 = 108°
Angle B = 2x = 2× 36 = 72°
Angle C = 3x = 3× 36 = 108°
Angle D = 2x = 2× 36 = 72°
Step-by-step explanation: