two consecutive circles are of radii 5cm and 3cm. find the length of the chords of the larger circle which touches the smaller circle..
Answers
Answered by
2
see draw a perpendicular from the centre to the chord...so u know that the perpendicular drawn from the centre to the chord bisects the chord...so
in the Triangle....using Pythagoras theorem....(5)^2-(3)^2 => 25-9 =>16...=>√16 = 4 cm..so the length of the chord = 4+4 = 8 cm
in the Triangle....using Pythagoras theorem....(5)^2-(3)^2 => 25-9 =>16...=>√16 = 4 cm..so the length of the chord = 4+4 = 8 cm
Answered by
3
N
let st is chord
now, OS = 5 cm and OT = 3 cm
==> ST² = OS² - OT² = 5² - 3² = 16
==> ST = 4 cm
Now, Chord Length PS = 2 ST = 2 x 4 = 8 cm
Thus, Chord Length = 8 cm
let st is chord
now, OS = 5 cm and OT = 3 cm
==> ST² = OS² - OT² = 5² - 3² = 16
==> ST = 4 cm
Now, Chord Length PS = 2 ST = 2 x 4 = 8 cm
Thus, Chord Length = 8 cm
Similar questions