Question

Two consecutive even integers are such that two-fifth of the smaller exceeds two-eleventh of the larger by 4. Then find the larger among them​

Answer 1

Answer:

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Answer

Let smaller number =x

Larger number =x+1

According to question,

⇒

4

x

−

5

x+1

=1

⇒

20

5x−4x−4

=1

⇒x=20+4

⇒x=24

⇒ Smaller number =24

⇒ Larger number =24+1=25

Hence, solved.