Question

two consecutive even number are such that the half of the larger number exceeds one fourth of the smaller number by 9. then larger number is ​

Answer 1

Step-by-step explanation:

LET ,1st consecutive even no. = x + 2

LET ,2nd consecutive even no. = x + 4

according to problem ,

=> (x + 4)/2 =(x + 2)/4 + 5

=> (x + 4)/2 = (x + 2 + 20)/4

=> (x + 4) = (x + 22)/2

=> 2x + 8 = x + 22

=> x = 14

So,

1st consecutive even no = 16

2nd consecutive even no = 18

∴ The larger number = 18

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