Question

Two consecutive even numbers are such that half of the number exceed one fourth of the smaller number by 5.then the larger number is .

Answer 1

The answer is given below :

Let us consider that the two consecutive even numbers are 2n and 2(n + 1), where n is a Natural number.

Half of the larger number

= 1/2 2(n + 1)

= n + 1

and one-fourth of the smaller number

= 1/4 2n

= n/2

By the given condition,

n + 1 = n/2 + 5

=> n - n/2 = 5 - 1

=> n/2 = 4

=> n = 8

So, the two even numbers are

2 × 8 and 2 × (8 + 1)

i.e., 16 and 18.

So, the larger number is 18.

Thank you for your question.

Answer 2

Hola there,

Let,
1st consecutive even no. = x + 2
2nd consecutive even no. = x + 4

According to the question,

=> (x + 4)/2 =(x + 2)/4 + 5

=> (x + 4)/2 = (x + 2 + 20)/4

=> (x + 4) = (x + 22)/2

=> 2x + 8 = x + 22

=> x = 14

So,
1st no. = 16

2nd no. = 18. ....Larger no.

Hope this helps.....:)