Question

two consecutive even numbers are such that half of the larger number exceeds one fourth of the smaller number by 5 then the larger number is

Answer 1

Answer:

Step-by-step explanation:

LET ,1st consecutive even no. = x + 2

LET ,2nd consecutive even no. = x + 4

according to problem ,

=> (x + 4)/2 =(x + 2)/4 + 5

=> (x + 4)/2 = (x + 2 + 20)/4

=> (x + 4) = (x + 22)/2

=> 2x + 8 = x + 22

=> x = 14

So,

1st consecutive even no = 16

2nd consecutive even no = 18

∴ The larger number = 18