Question

Two consecutive integers have a sum of 79 . Find the integers.

Answer 1

Let the integers be x
ATQ.
x+x+1=79
2x+1=79
2x=79-1
2x=78
x=78/2
x=39
The integers are x=39 and x+1=39+1=40

Answer 2

Let the first integer be x and let the 2nd integer be x + 1

Given, their sum = 79


According to the question,

x + x + 1 = 79

2x + 1 = 79

2x = 79 - 1

2x = 78

x = $\dfrac{78}{2}$

x = 39



First integer = x = 39

Second integer = x + 1 = 39 + 1 = 40