Question

two consecutive natural numbers are such that one fourth of the smaller exceeds one fifth of the greater by 1. Find the numbers

Answer 1

let one number be x

other number= x+1

A/Q

x/4=(x+1)/5  +1

x/4-(x+1)/5=1

5x-4x-4/20=1

x-4=20

x=24

therefore numbers are 24 and 25

Answer 2

1st number = x 380           2nd number = x +1

1/5x - 1/4x+1 = 1

4x - 5x + 20 / 20 = 1

-1x/20 = 1 - 20

-1x/20 = -19

x = -19 * 20/-1

x = 380 (1st number)

x + 1 = 380 +1 = 381 (2nd number)

hope this answer with the working helps you