two consecutive numbers in which the sum of 3 times the first number and the square of second number is 85.find the number
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Answer:7,8
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Step-by-step explanation:
Let the numbers be x and x+1
According to given condition-
3x+(x+1)^2 = 85
3x+x^2+x2+1=85
x^2+5x-84=0
x^2 - 7x + 12x - 84 =0
x(x-7) + 12(x-7) = 0
x= 7 OR x= -12
x+1= 7+1 = 8
Therefore the two consecutive numbers are 7 and 8
Done
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