Two consecutive numbers in which the sum of 3 times the first number and the square of the second number is 85.find the number
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Step-by-step explanation:
LET THE NUMBERS BE X, (X+1)
∴3X+(X+1)²=85
⇒3X+X²+2X+1=85
⇒X²+5X+1=85
⇒X²+5X-84=0
⇒X²+12X-5X-84=0
⇒X(X+12)-5(X+12)=0
⇒(X-5)(X+12)=0
∴X-5=0
⇒X=5
∴X+12=0
⇒X=-12
AS ,X=-12 IT IS REJECTED
∴X=5
∴THE NUMBERS ARE 5 AND 6
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