Two consecutive odd positive integers whose product is 323
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hi, my lovely friend here is Ur answer.
let the consecutive odd integers be 2x+1
and 2x+3 and according to question products of their sum =323
so(,2x+1)×(2x+3)=323
4xsquare +4x+3=323
4xsquare +4x-320=0
adding 4on both si
let the consecutive odd integers be 2x+1
and 2x+3 and according to question products of their sum =323
so(,2x+1)×(2x+3)=323
4xsquare +4x+3=323
4xsquare +4x-320=0
adding 4on both si
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