Two consecutive positive even numbers the sum of whose square is 340
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Step-by-step explanation:
let the numbers be X and X+2 then
( X) ^2 + ( X+2) ^2 = 452
x^2 + x^2 +4+ 4x= 452
2 x^2 + 4x - 448 = 0
x^2 + 2x - 224 = 0
x^2 + 16x -14x -224 = 0
X( X+16) - 14( X+16)= 0
( X+16)(X-14) =0
X = 14,-16
the numbers are either 14 and 16 or -16 and -14
Answered by
1
let the two consecutive positive even numbers be x,x+2
x^2+(x+2)^2=340
x^2+x^2+4+4x=340
2x^2+4x=336
2(x^2+2x-168)=0
x^2+2x-168=0
x^2+14x-12x-168=0
x(x+14)-12(x+14)=0
Therefore,x=12,-14
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