Question

two consecutive positive numbers are such that the sum of their square is 113 find the two numbers and the answer is 7and 8

Answer 1

Answer:

let two consecutive positive numbers then according to the question, we have

➟A+(A+12-113,

➟A2+A2+2A+1=113,

➟2A2+2A-113-1,

➟2(A+A)=112,

then

➭A+A 56,

➭A+A-56-0,

➭A(8-7)A-56-0,

➭A2+8A-7A-56-0,

➭A(A+8)-7(A+8)=0,

➭(A+8) A-7)-0,

then

➼A-7-0,

➼A-7,

∴first number=7,

∴first number=7,second number=7+1-8