Math, asked by adivyasingh05, 5 months ago

Two consecutive sides of a parallelogram are x-2y+2=0 and 2x+y-16=0. One of the diagonals of the parallelogram is 3x-y-9=0. Then calculate the area of the parallelogram.

Answers

Answered by gmabinithi
0

Answer:

One of the diagonals of the parallelogram is 3x-y-9=0. Then calculate the area of the - 249… ... Two consecutive sides of a parallelogram are x-2y+2=0 and 2x+y-16=0.

Answered by rohanjhajhria7878
1

answer

x - 2y + 2 = 0 \\  \\ x - 2y =  - 2 \\ x - y =  \frac{ - 2}{2} \\ x - y =  - 1

2x + y - 16 = 0 \\ 2x + y = 16 \:  \:  \\ x + y =  \frac{16}{2}  \\ x + y = 8

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