Physics, asked by Muffins, 11 months ago

Two constant forces F1=2 I - 3j +3k (N) and F2=I+j-2k (N) act on a body and displace it from position r1= I+2j-2k(m) to position r2 =7i + 10j +5k (m) . What is work done ...

please answer me guys

Answers

Answered by nikkusing09876543

5

Answer:

The work done by the body is 9 joules.

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Answered by ratanshakya789

4

Hey mate here is ur answer

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