Two containers A and B begin with equal volumes of liquid.120 ml is then poured from A to B. Container B now contains 4 times as much liquid as A. Find the volume of liquid left in container A at the end
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Answer:
80ml
Step-by-step explanation:
Let volume of water in A be x.
Then, B = x (ATQ)
Now,
When 120ml is taken from A and poured to B, then B=4 times of A
ATQ
(B + 120) = 4(A - 120m)
=) x + 120ml = 4x - 480
=) 120 +480 = 4x - x
=) 600 = 3x
=) x = 200
Volume of liquid left in container A at the end = A - 120= x - 120 = 80ml
Hence, the volume of liquid left in container A is 80ml.
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