Question

two containers A and B contain mix of water and milk in the ratio of 5:2 and 7:6 respectively find the ratio in which these two mixtures can be mixed so that a new mixture formed in the container C in the ratio of 8:5
A 2:7
B 7:9
C 9:7
D 5:7​

Answer 1

Answer:

hi friends

Step-by-step explanation:

Two containers A and B mix of water and milk in the ratio 5 : 2 and 7 : 6 respectively. Find the ratio in which these two mixtures can be mixed so that a new mixture form in the container with ratio of 8 : 5?

Let a and b be the amount of mixture taken from A and B respectively and poured to container C.

Amount of water in C = (5a/(5+2))+ (7b/(7+6)) = (5a/7)+(7b/13)

Amount of milk in C = (2a/(5+2))+ (6b/(7+6)) = (2a/7)+(6b/13)

Target ratio of water and milk = 8/5

[(5a/7)+(7b/13)]/ [(2a/7)+(6b/13)] = 8/5

By simplification,

a/b = 7/9

Ans: Ratio = 7:9

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Answer 2

Two mixtures of ratio 5 :2 and 7 : 6  must be mixed in 7 : 9 ratio to get final mixture  8 : 5

Given : Two containers A and B contain mix of water and milk in the ratio of 5:2 and 7:6 respectively  

To Find :Ratio in which these two mixtures can be mixed so that a new mixture formed in the container C in the ratio of 8:5

Solution:

Let say solutions A and B are mixed in m : n ratio

Container A  Water : Milk = 5 : 2

Water = 5m/7

Milk  = 2m/7

Container B  Water : Milk = 7  : 6

Water =7n/13

Milk  = 6n/13

Water = 5m/7 + 7n/13

= ( 65m + 49n)/91

Milk = 2m/7  + 6n/13

= (26m + 42n)/91

Rati  = 8 : 5

=>  ( 65m + 49n) /  (26m + 42n)  = 8/5

=> 325m + 245n  = 208m  + 336n

=> 117m  = 91n

=> 9m = 7n

=> m/n = 7/9

=> m : n = 7 : 9

correct option is  B 7:9

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