Two containers A and B contain the same gas . If the pressure, volume and absolute temperature of the gas in A are twice as compared to that of gas in B , and if the mass of the gas B is Xg , the mass of gas in A is
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Both vessels contain same gas ∴molar mass of gas in both the vessels is same.
The mass of the gas in B is xg
Let mss of gas in A be yx
In vessel B PV=nRT
TPV=n (R is gas constant)
TPV=MxM=x(PVT)⟶eqn(1)
In vessel A 2P.2V=nR.2T2T2P.2V=nT2PV=MyM=y(2PVT)⟶eqn(2)
From equation (1) and equation(2)
x(PVT)=y(2PVT)x=2y2x=y
Thus, the mass of the gas in A will be (2x)g
Explanation:
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