Question

Two coplanar forces with magnitude 20 kN and 15 kN are oriented with angle of inclination What should be their resultant in magnitude and direction if first force acts away from their inter se second force acts towards the intersection?

Answer 1

Answer:

Let, P and Q be the two forces having magnitudes 15 Newtons and 20 Newtons respectively. They are acting at an angle α = 60°.

Let, R be the resultant vector. Vector R acts at an angle θ with vector P.

So, |R^2| = 15^2 + 20^2 + 2 * 15 * 20 * cos 60°

Or, |R^2| = 225 + 400 + 300 = 925

Or, |R| = 30.4138 Newtons

So, tan θ = (20 * sin 60°) / {15 + 20 * cos 60°}

Or, tan θ = (10√3) / (15 + 10) = (10√3) / 25

Or, tan θ = (2√3) / 5 = 0.69282

Or, θ = 34.715°

So, magnitude of the resultant force = 30.4138 Newtons and the resultant force acts at an angle 34.715° with the 15 Newton magnitude force.

Answer 2

AnswerR=18.03KN 46.1’

Step-by-step explanation: