Question

Two copper balls, each weighing 10g are kept in air 10 cm
apart. If one electron from every 10 atoms is transferred
from one ball to the other, the coulomb force between
them is (atomic weight of copper is 63.5)
(a) 2.0 × 10 10 N
(b) 2.0 x 104 N
(c) 2.0 x 108 N
d) 2.0 x10N
​

Answer 1

Answer:

The answer is  2.0×10^8 N

Explanation:

We know that Number of electrons, n  

=  6.023 ×10^23/63.5×10×1/10^6=

6×10^18/63.5  

Now the magnitude of the charge on each ball is

q = 6×10^18×1.6×10−19^/63.5 C  

Or

q = 1.5×10^−2 C  

Now calculate the force F

F = 9×10^9×1.5×10^−2×1.5×10^−2/(10/100) N  

= 2.0×10^8 N

Thus the coulomb force between the copper balls is  2.0×10^8 N.

Answer 2

Answer:

option c is the answer....

and to get the answer it should be 10⁶ atoms in the question... rest in attachment