two copper conductors A,B carrying currents of 1A and 1.2A respectively. if the radii are in the ratio of 2:3 then the drift speed of the electrons in the two conductors are in the ratio
Answers
Answered by
7
Answer:
16:1
Explanation:
I = neav
where I - current
n - carrier per unit volume
a - csa
v - drift velocity
Radius of 1st wire = r
Radius of 2nd wire = 2r
Current in 1st wire = I
Current in 2nd wire = 4I
1st wire area = pi . r²
2nd wire area = pi . (2r)²
I₁/I₂ = a₁v₁/a₂v₂
Therefore, 4I/I = pi/r² v₁ / 4 pi. r² . v₂
Therefore, v₁/v₂ = 16/1
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Answered by
0
Answer: 15:8
Explanation:
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