Question

two copper conductors A,B carrying currents of 1A and 1.2A respectively. if the radii are in the ratio 2:3 then the drift speed of the electrons in the two conductors are in the ratio

Answer 1

Answer:

16:1

Explanation:

I = neav

where I - current

n - carrier per unit volume

a - csa

v - drift velocity

Radius of 1st wire = r

Radius of 2nd wire = 2r

Current in 1st wire = I

Current in 2nd wire = 4I

1st wire area = pi . r²

2nd wire area = pi . (2r)²

I₁/I₂ = a₁v₁/a₂v₂

Therefore, 4I/I = pi/r² v₁ / 4 pi. r² . v₂

Therefore, v₁/v₂ = 16/1