two copper pieces each of mass 0.0635 kg are placed at a distance 0.1 m from each other . One electron from each atom of piece 1 is transferred to piece 2 of copper . charges on piece 1 and piece 2 after transfer of electrons will be ?
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First of all, we will Calculate the number of atoms in 0.0635 kg of Copper
0.0635 kg= 63.5 g = 1 mole = 6.022 × 10^23 atoms
Now, 6.022×10^23 electrons are transferred from copper 1 to copper 2
charge on 6.022×10^23 electrons = 6.022×10^23 × 1.602 x 10^-19 coulombs (C)
=9.64×10^4 Coulombs
This is the answer
0.0635 kg= 63.5 g = 1 mole = 6.022 × 10^23 atoms
Now, 6.022×10^23 electrons are transferred from copper 1 to copper 2
charge on 6.022×10^23 electrons = 6.022×10^23 × 1.602 x 10^-19 coulombs (C)
=9.64×10^4 Coulombs
This is the answer
Answered by
14
Mass of each copper piece = 0.0635 kg = 63.5 g
molecular mass of Copper = 63.5 g/mol
∴ mole = given weight/molecular weight = 63.5/63.5 = 1
∵ 1 mole = 6.023 × 10²³ atoms
And question says , each atom transfers one electron from piece one to piece 2
∴ number of electrons transfer = 6.023 × 10²³
∴ total charge = number of electron transfer × charge on an electron
= 6.023 × 10²³ × 1.6 × 10⁻¹⁹ C
= 9.6368 × 10⁴ C
Hence, magnitude of charge developed on each piece of copper = 96368 C
molecular mass of Copper = 63.5 g/mol
∴ mole = given weight/molecular weight = 63.5/63.5 = 1
∵ 1 mole = 6.023 × 10²³ atoms
And question says , each atom transfers one electron from piece one to piece 2
∴ number of electrons transfer = 6.023 × 10²³
∴ total charge = number of electron transfer × charge on an electron
= 6.023 × 10²³ × 1.6 × 10⁻¹⁹ C
= 9.6368 × 10⁴ C
Hence, magnitude of charge developed on each piece of copper = 96368 C
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