Question

two copper wire have their masses in fhe ratio 2:3 and lengths in the ratio 3:4 then the ratio of their resistances is​

Answer 1

Answer:

4:5

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Answer 2

Answer:

$\huge{\boxed{\mathcal\purple{♡}{\blue{Hey}\purple{♡}}}}$

Explanation:

Masses of a two copper wire are in ratio = 2:3

Lengths are in ratio = 3:4

So for masses let the common ratio be x,

So for first wire  its mass is = 2x.

For second wire its mass is 3x.

For length let the common ratio be l.

So for first wire  its mass is = 3l.

For second wire its mass is 4l.

We know,

Since,

So,

So ,

For First wire,

For First wire,

On dividing resistance of first wire by second,

on solving we get,

So, the ratio of their resistances will be  27:32.

4.8

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