Question

Two copper wires A and B have their cross-sectional

areas in the ratio 1 : 2 and lengths in the ratio 2 : 1

respectively. The ratio of the resistivities of A and B

will be

and how?(science question)

Answer 1

Since R=ro*L/A
ro is resistivity.
Since both are copper R-resistance will be same.
ro¹L¹/A¹=ro²L²/A²
ro¹/ro²=L²A¹/L¹A²
=1/4
=> 1:4 RATIO

Answer 2

Since R=ro*L/A
ro is resistivity.
Since both are copper R-resistance will be same.
ro¹L¹/A¹=ro²L²/A²
ro¹/ro²=L²A¹/L¹A²
=1/4
=> 1:4 Ratio