Question

Two copper wires A and B of length 30m and 10m radius 2cm and 1 cm respectively compare the restance of two wire .

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Answer 1

Answer:

As both the wires are of same material, therefore their resistivity will be same.

Now, the length of wire A= 30m=L

Radius of wire A=2cm=0.02m

Area of wire=pie*r*r=A

Area of wire A=pie*0.02r*0.02r

= 0.0004r*square pie

=0.0004A

Reaistance of a wire=resistivity*L/A =R

Resistance of wire A= 30L/0.0004A=7500R

Similarly, resistivity of wireB=10L/0.0001A=10000R

So resistance of wire B is more than wire A

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Answer 2

Answer:

heya

here is the answer

Explanation:

The ratio will be 3:2

By using the formula, R=rho×l/pi×r×r

Where rho is the constant(which gets cancelled as it is a ratio)

l is the length of wire

r is the radius of wire

R is the resistance

We see that pi and rho gets cancelled.

On converting the units from cm to m or vice versa we get the answer as 3:2