Question

Two copper wires have cross-sectional areas in the ratio 4:3 and length in the ratio 3:4. Find the ratio of their resistances

Answer 1

Answer:

Step-by-step explanation:

R∝ L/A

L1/L2 = 3/4

A1/A2 = 4/3

R1/R2 =( L1 A2)/(L2 A1)

          =(3×3)/(4×4)

          =9/16

R1:R2 =9 :16