Question

two cows are tied with arope to a pole in the middle of a grass field. the radius of the ropes are 18 m and 11 m respectively . find the difference in their area covered while grazing the grass.​

Answer 1

Step-by-step explanation:

Difference in area covered

$= \pi \times {r1}^{2} - \pi \times {r2}^{2}$

$= \pi \times ( {18}^{2} - {11}^{2} )$

$= \pi \times (324 - 121)$

$= \pi \times 203$

$= \frac{22}{7} \times 203 = 22 \times 29 = 638sq.m$

Answer 2

The difference in their area would be 638 sq. m.

Step-by-step explanation:

Since we have given that

Radius of rope of first cow = 18 m

Radius of rope of second cow = 11 m

We need to find the difference in their area covered while grazing the grass.

So, the Difference in their area covered while grazing the grass is given by

$\pi (18)^2-\pi (11)^2\\\\=\pi (18^2-11^2)\\\\=\pi \times 203\\\\=\dfrac{22}{7}\times 203\\\\=638\ m^2$

Hence, the difference in their area would be 638 sq. m.

# learn more:

A cow is tied to a pole in a grass field using a rope which is 5.6 meter long. find the area where cow can graze the grass

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