Question

Two cricles of qusl radii are inscribed in a rectangle ABCD .if AB=28cm find the are of the shaded portion​

Answer 1

Answer:

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Answer 2

2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?

2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?3-in-1 protection for moms-to-be helps protect baby too.

2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?3-in-1 protection for moms-to-be helps protect baby too.2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?

2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?3-in-1 protection for moms-to-be helps protect baby too.2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?The important things here are:

2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?3-in-1 protection for moms-to-be helps protect baby too.2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?The important things here are:a=log10(10a)

2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?3-in-1 protection for moms-to-be helps protect baby too.2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?The important things here are:a=log10(10a) alog10(b)=log10(ba)

2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?3-in-1 protection for moms-to-be helps protect baby too.2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?The important things here are:a=log10(10a) alog10(b)=log10(ba) log10(a)−log10(b)=log10(ab)

2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?3-in-1 protection for moms-to-be helps protect baby too.2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?The important things here are:a=log10(10a) alog10(b)=log10(ba) log10(a)−log10(b)=log10(ab) Division and Subtraction left to right.

2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?3-in-1 protection for moms-to-be helps protect baby too.2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?The important things here are:a=log10(10a) alog10(b)=log10(ba) log10(a)−log10(b)=log10(ab) Division and Subtraction left to right.So

2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?3-in-1 protection for moms-to-be helps protect baby too.2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?The important things here are:a=log10(10a) alog10(b)=log10(ba) log10(a)−log10(b)=log10(ab) Division and Subtraction left to right.So2−log10(2)−2log10(5)=

2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?3-in-1 protection for moms-to-be helps protect baby too.2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?The important things here are:a=log10(10a) alog10(b)=log10(ba) log10(a)−log10(b)=log10(ab) Division and Subtraction left to right.So2−log10(2)−2log10(5)= log10(100)−log10(2)−log10(25)=

2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?3-in-1 protection for moms-to-be helps protect baby too.2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?The important things here are:a=log10(10a) alog10(b)=log10(ba) log10(a)−log10(b)=log10(ab) Division and Subtraction left to right.So2−log10(2)−2log10(5)= log10(100)−log10(2)−log10(25)= log10(1002)−log10(25)=

2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?3-in-1 protection for moms-to-be helps protect baby too.2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?The important things here are:a=log10(10a) alog10(b)=log10(ba) log10(a)−log10(b)=log10(ab) Division and Subtraction left to right.So2−log10(2)−2log10(5)= log10(100)−log10(2)−log10(25)= log10(1002)−log10(25)= log10(50)−log10(25)=

2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?3-in-1 protection for moms-to-be helps protect baby too.2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?The important things here are:a=log10(10a) alog10(b)=log10(ba) log10(a)−log10(b)=log10(ab) Division and Subtraction left to right.So2−log10(2)−2log10(5)= log10(100)−log10(2)−log10(25)= log10(1002)−log10(25)= log10(50)−log10(25)= log10(5025)=

2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?3-in-1 protection for moms-to-be helps protect baby too.2-log10(2)-2log10(5) is written as a single logarithm log10(2). How can I do this?The important things here are:a=log10(10a) alog10(b)=log10(ba) log10(a)−log10(b)=log10(ab) Division and Subtraction left to right.So2−log10(2)−2log10(5)= log10(100)−log10(2)−log10(25)= log10(1002)−log10(25)= log10(50)−log10(25)= log10(5025)= log10(2)