Question

.Two cross paths, each of width 12 m, intersect at
right angles through the centre of a rectangular
park of length 650 m and breadth 200 m and
parallel to its sides. Find the area of the path. Give
the answer in hectares.​

Answer 1

Answer:

20.01 hectare

Step-by-step explanation:

From the question it is given that,

Length of the park (L) = 700 m

Breadth of the park (B) = 300 m

Then,

Area of the park = length × breadth

= 700 × 300

= 210000 m^2

Let us assume that ABCD is the one cross road and EFGH is another cross road in the park.

The length of ABCD cross road = 700 m

The length of EFGH cross road = 300 m

Both cross road have the same width = 10 m

Then,

Area of the ABCD cross road = length × breadth

= 700 × 10

= 7000 m^2

Area of the EFGH cross road = length × breadth

= 300 × 10

= 3000 m^2

Area of the IJKL at center = length × breadth

= 10 × 10

= 100 m^2

Area of the roads = Area of ABCD + Area of EFGH – Area of IJKL

= 7000 + 3000 – 100

= 10000 – 100

= 9900 m^2

We know that, for 1 hectare = 10000 m^2

Hence, area of roads in hectare = 9900/10000

= 0.99 hectare

Finally, Area of the park excluding roads = Area of park – Area of the roads

= 210000 – 9900

= 200100 m^2

= 200100/10000

= 20.01 hectare