Question

Two cross paths, each of width 12 m, intersect
right angles through the centre of a rectangular
park of length 650 m and breadth 200 m and
parallel to its sides. Find the area of the path. Give
the answer in hectares.​

Answer 1

Step-by-step explanation:

width =12 m

length of first parallel road 650 m

area of first road 650×12= 7,800 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750