two Cross Road each of which 5 metre run at right angles through the centre of a rectangular Park of length 700 metre and breadth 300 parallel to its side find the area of the roads also find the cost of cementing the road at the rate of rupees 105 per metre square
Answers
Answer:
Here, PQ = 10 m and PS = 300 m, EH = 10 m and EF = 700 m
And KL = 10 m and KN = 10 m
Area of roads
( diagram)
= Area of PQRS + Area of EFGH – Area of KLMN
[∵ KLMN is taken twice, which is to be subtracted]
= PS x PQ + EF x EH – KL x KN
= (300 x 10) + (700 x 10) – (10 x 10)
= 3000 + 7000 – 100
= 9,900 m2
Area of road in hectares, 1 m2= 110000 hectares
∴ 9,900m2= 990010000 = 0.99 hectares
Now, Area of park excluding cross roads = Area of park – Area of road
= (AB x AD) – 9,900
= (700 x 300) – 9,900
= 2,10,000 – 9,900
= 2,00,100 m2
= 20010010000 hectares = 20.01 hectares
Here, PQ = 10 m and PS = 300 m, EH = 10 m and EF = 700 m
And KL = 10 m and KN = 10 m
Area of roads
= Area of PQRS + Area of EFGH – Area of KLMN
[∵ KLMN is taken twice, which is to be subtracted]
= PS x PQ + EF x EH – KL x KN
= (300 x 10) + (700 x 10) – (10 x 10)
= 3000 + 7000 – 100
= 9,900 m2
Area of road in hectares, 1 m2= 110000 hectares
∴ 9,900m2= 990010000 = 0.99 hectares
Now, Area of park excluding cross roads = Area of park – Area of road
= (AB x AD) – 9,900
= (700 x 300) – 9,900
= 2,10,000 – 9,900
= 2,00,100 m2
= 20010010000 hectares = 20.01 hectares
Step-by-step explanation:
