two cross road each of width 5cm run at right angle through the centre of rectangular park of lenght 70m and 45mand parallel to its side .find area of road
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area of ABCD= 7500*5
=37500cm^2
area of efgh= 4500*5
=22500 cm^2
area of mid square=5*5
=25cm^2
area of road= area of ABCD+area of efgh -area of mid square
=37500+22500-25
=60000-25
=59975cm^2
=37500cm^2
area of efgh= 4500*5
=22500 cm^2
area of mid square=5*5
=25cm^2
area of road= area of ABCD+area of efgh -area of mid square
=37500+22500-25
=60000-25
=59975cm^2
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