Question

Two cross road each of width 5m, run through the centre of a rectangular park of length 75m and breadth 55m. Find the area of the path and the cost of pavint at the rate of (rupees - 130) per m²​

Answer 1

Answer:

answer of the similar question

Step-by-step explanation:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that  lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

                                           

=(350+225)−25

=575−25

=550sqm

​

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750